A) \[1{}^\circ \]carbon
B) \[2{}^\circ \]carbon
C) \[3{}^\circ \]carbon
D) both \[1{}^\circ \] and \[2{}^\circ \]carbon
E) both \[2{}^\circ \]and \[3{}^\circ \]carbon
Correct Answer: D
Solution :
The formula of glycerine is \[\begin{align} & {}^{\alpha }C{{H}_{2}}-OH\xleftarrow{{}}1{}^\circ \,alcohol \\ & \underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{{}^{\beta }CH}}}\,-OH\xleftarrow{{}}2{}^\circ \,alcohol \\ & {}^{\alpha }C{{H}_{2}}-OH\xleftarrow{{}}1{}^\circ \,alcohol \\ \end{align}\] Thus, it contains \[1{}^\circ \] and \[2{}^\circ \]carbon atoms.
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