A) Diamminedichloroplatinum (II)
B) Tetramminedichlorocobalt (III) chloride
C) Potassium hexacyanoferrate (II)
D) Hexaaquochromium (III) bromide
E) Pentacarbonyl iron (0).
Correct Answer: C
Solution :
The molar conductivity of potassium hexacy-anoferrate (II) i.e., \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]is highest because it gives maximum number of ions on ionisation. \[{{K}_{4}}[Fe{{(CN)}_{6}}]\xrightarrow{{}}4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{4-}}\]
You need to login to perform this action.
You will be redirected in
3 sec
