CMC Medical CMC-Medical VELLORE Solved Paper-2011

  • question_answer
    The enol form of acetone after treatment with \[{{D}_{2}}O,\]gives

    A)  \[{{H}_{3}}C-\underset{OD}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,=C{{H}_{2}}\] 

    B)  \[{{H}_{3}}C-\underset{O}{\mathop{\underset{\mathbf{||}}{\mathop{C}}\,}}\,-C{{D}_{3}}\]

    C)  \[{{H}_{2}}C=\underset{OH}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,-C{{H}_{2}}D\]              

    D)  \[{{H}_{2}}C=\underset{OH}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,-CH{{D}_{2}}\]

    E)  \[{{D}_{2}}C=\underset{OD}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,-C{{D}_{3}}\]

    Correct Answer: A

    Solution :

                    \[\underset{enol\,form\,\,of\,acetone}{\mathop{C{{H}_{3}}-\underset{OH}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,+{{D}_{2}}O\to {{H}_{3}}C-\underset{OD}{\mathop{\underset{\mathbf{|}}{\mathop{C}}\,}}\,=C{{H}_{2}}\]


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