A) \[10\pi \,mV\]
B) \[20\pi \,mV\]
C) \[\frac{\pi }{10}\,V\]
D) \[\frac{\pi }{10}\,V\]
Correct Answer: A
Solution :
The induced emf between centre and rim of the rotating disc \[E=\frac{1}{2}B\omega {{R}^{2}}\] \[=\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}}\] \[=10\pi \times {{10}^{-3}}V\] \[=10\pi \,mV\]
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