A) \[2\,\,m\text{/}{{s}^{2}}\]
B) \[4\,\,m\text{/}{{s}^{2}}\]
C) \[10\,\,m\text{/}{{s}^{2}}\]
D) \[14\,\,m\text{/}{{s}^{2}}\]
Correct Answer: D
Solution :
Average acceleration \[=\frac{\text{Change in velocity}}{\text{Time taken}}\] \[=\frac{{{v}_{2}}-{{v}_{1}}}{{{t}_{2}}-{{t}_{1}}}\] Velocity at 2s, \[{{v}_{1}}=[10+2{{(2)}^{2}}]=18\,\,m/s\] Velocity at 5s, \[{{v}_{2}}=[10+2{{(5)}^{2}}]=60\,\,m/s\] \[\therefore \] \[{{a}_{av}}=\frac{60-18}{5-2}=\frac{42}{3}\] \[=14\,m/{{s}^{2}}\]
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