CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    4.5 g of a metallic chloride contains 35.5 g of chlorine, the equivalent weight of the metal is

    A)  19.5                      

    B)  35.5

    C)  39                                         

    D)  78.0

    Correct Answer: C

    Solution :

                    Equivalent weight of metal\[=\frac{\text{wt}\text{.}\,\text{of}\,\text{metal}}{\text{wt}\text{.}\,\text{of}\,\text{chlorine}}\times 35.5\]\[=\frac{(74.5-35.5)\times 35.5}{35.5}=39\]


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