question_answer

\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\]is not. It is because

A)  the electronegativity of F is greater than that of O

B)  \[{{H}_{2}}O\]involves hydrogen bonding whereas \[Be{{F}_{2}}\]is a discrete molecule

C)  \[{{H}_{2}}O\]is linear and \[Be{{F}_{2}}\] is angular

D)  \[{{H}_{2}}O\]is angular and \[Be{{F}_{2}}\]is linear

Correct Answer: D

Solution :

                The structure of\[{{H}_{2}}O\]is angular V shape and has\[s{{p}^{3}}\]hybridisation and bond angle is\[105{}^\circ \]. Its dipole moment value is positive or more than zero. In \[Be{{F}_{2}},\]structure is linear due to sp hybridisation\[(\mu =0),\]Thus, due to\[(\mu =0),\]\[{{H}_{2}}O\] is dipolar and due to\[\mu =0,\]\[Be{{F}_{2}}\]is linear.