A) \[N{{a}_{2}}{{O}_{2}}\]
B) \[{{O}_{3}}\]
C) \[{{N}_{2}}O\]
D) \[K{{O}_{2}}\]
Correct Answer: D
Solution :
For \[K{{O}_{2}},\]\[O_{2}^{-}\] has unpaired electron, so, it is paramagnetic \[O_{2}^{-}\,\,\,17)\]\[\sigma \,1{{s}^{2}},\,\,{{\sigma }^{*}}1{{s}^{2}},\,\,\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}},\,\,\sigma 2p_{x}^{2}\]\[(\pi 2p_{y}^{2\grave{\ }}=\pi 2p_{z}^{2}),\,\,{{\pi }^{*}}2p_{y}^{2\grave{\ }}={{\pi }^{*}}p_{z}^{1}\]
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