A) \[{{F}_{2}},\,C{{l}_{2}}\]and\[B{{r}_{2}}\]
B) \[C{{l}_{2}},\,{{F}_{2}}\]and\[B{{r}_{2}}\]
C) \[C{{l}_{2}},\,B{{r}_{2}}\]and\[{{F}_{2}}\]
D) \[B{{r}_{2}},\,C{{l}_{2}}\]and\[{{F}_{2}}\]
Correct Answer: B
Solution :
Electron affinity (in kJ \[\text{mo}{{\text{l}}^{\text{-1}}}\]) of F = 332.6, Cl = 348.5, Br = 324.7 and I = 295.5. Chlorine has highest electron affinity value, So, according to question the correct order will be\[C{{l}_{2}}>{{F}_{2}}>B{{r}_{2}}\].
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