A) \[395.4{}^\circ C\]
B) \[144{}^\circ C\]
C) \[887.4{}^\circ C\]
D) \[18{}^\circ C\]
Correct Answer: A
Solution :
Initial temperature \[{{T}_{1}}=18{}^\circ C=291\,K\] \[{{V}_{2}}=\frac{{{V}_{1}}}{8}\] For adiabatic expression \[{{T}_{1}}V_{1}^{\gamma -2}={{t}_{2}}v_{2}^{\gamma -2}\] \[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -2}}\] \[=298\times {{8}^{1.4-2}}\] \[=291\times 2.297\] \[=668.3\,K\] \[=395.4\,C\]
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