A) \[\frac{1}{{{\omega }^{2}}}\]
B) \[\omega \]
C) \[\frac{1}{{{a}^{2}}}\]
D) \[{{a}^{2}}\]
Correct Answer: D
Solution :
The total energy of simple hormonic motion is given by E = Kinetic energy + potential energy or \[E=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{y}^{2}})+\frac{1}{2}m\,{{\omega }^{2}}{{y}^{2}}\] or \[E=\frac{1}{2}{{\omega }^{2}}{{a}^{2}}\] Here, \[E\propto {{a}^{2}}\]
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