A) \[\frac{2}{3}\]
B) \[\frac{4}{9}\]
C) \[\frac{5}{9}\]
D) \[\frac{2}{9}\]
Correct Answer: C
Solution :
\[E=m{{c}^{2}}\] If speed of light were \[\frac{2}{3}\]of its present value, then \[E=m{{\left( \frac{2}{3}c \right)}^{2}}=4/9\,m{{c}^{2}}=4/9\,E\] Energy decreased by \[E-E=E-4\text{/}9\,E=5\text{/}9E\]
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