question_answer

When benzene sulphonic acid and p-nitrophenol are treated with \[NaHC{{O}_{3}}\] the gases released respectively are

A)  \[S{{O}_{2}},\,C{{O}_{2}}\]                        

B)  \[C{{O}_{2}},\,C{{O}_{2}}\]

C)  \[S{{O}_{2}},\,NO\]                       

D)  \[S{{O}_{2}},\,N{{O}_{2}}\]

Correct Answer: B

Solution :

                Benzene sulphonic acid and p-nitrophenol react with \[NaHC{{O}_{3}}\] and evolve \[C{{O}_{2}}\]gas. Because benzene sulphonic acid and p-nitrophenol are stronger acids, so they are capable of to evolve\[C{{O}_{2}}\]with\[NaHC{{O}_{3}}\].\[HCO_{3}^{-}+{{H}^{+}}\xrightarrow{{}}{{H}_{2}}O+C{{O}_{2}}\uparrow \]