CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    The normal oxidation potential of zinc referred to the standard hydrogen electrode is 0.76V and that of copper is 0.34V at \[25{}^\circ C,\]when excess of zinc is added to solution of copper sulphate, zinc displaces copper till equilibrium is reached. What is the ratio of concentration to\[Z{{n}^{2+}}\]to\[C{{u}^{2+}}\]ions at equilibrium?

    A)  \[1.69\times {{10}^{37}}:1\]      

    B)  \[1.243\times {{10}^{22}}:1\]

    C)  \[1:1679\times {{10}^{37}}\]     

    D)  \[1:1.24243\times {{10}^{22}}\]

    Correct Answer: A

    Solution :

                    The reaction is \[Zn+CuS{{O}_{4}}\xrightarrow{{}}Cu+ZnS{{O}_{4}}\] \[Zn+C{{u}^{2+}}\xrightarrow{{}}Cu+Z{{n}^{2+}}\] \[{{E}_{cell}}=E{{{}^\circ }_{cell}}-\frac{0.0591}{2}\,\log \,\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] At equilibrium, \[{{E}_{cell}}=0\] \[E{{{}^\circ }_{cell}}=\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=\frac{2\times E{{{}^\circ }_{cell}}}{0.0591}\] \[(E{{{}^\circ }_{cell}}=0.76+0.034=1.10\,V)\] \[=2\times 1.10/0.0591=37.225\] \[\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=1.679\times {{10}^{37}}:1\]


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