CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    For the following metals A, B, C, D react with each other (N.R. = no reaction).
    \[A+{{B}^{+}}\to N.\,R\] \[;\,\,B+{{C}^{+}}\to N.\,R\]
    \[B+{{D}^{+}}\to {{B}^{+}}+D\] \[;\,\,C+{{D}^{+}}\to {{C}^{+}}+D\]
    \[A+C\to {{C}^{+}}+A\] \[;\,\,D+{{A}^{+}}\to {{D}^{+}}+A\]
    What is the order of the metals in increasing reducing strength?

    A)  \[B<D<A<C\]   

    B)  \[C<B<D<A\]

    C)  \[A<D<B<C\]   

    D)  \[D<C<A<B\]

    Correct Answer: C

    Solution :

                    Stronger reducing metal displaces ions of weaker reducing metals from the solution. From first two reactions A is weaker reducing agent than 6. 6 is weaker reducing agent than C. Reducing power: A < B < C Form the next two reactions; B is stronger reducing agent than D C is stronger reducing agent than D Form the last reactions, D is stronger reducing agent than A. Thus, overall reducing strength is A < D < B < C.


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