CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    Calculate the number of revolutions per second made around the nucleus by an electron in the third Bohrs orbit of a hydrogen atom.

    A)  \[2.43\times {{10}^{14}}\]                          

    B)  \[2.43\times {{10}^{15}}\]

    C)  \[2.43\times {{10}^{16}}\]                          

    D)  \[2.43\times {{10}^{17}}\]

    Correct Answer: A

    Solution :

                    \[v=2.18\times {{10}^{6}}\left( \frac{Z}{n} \right)m{{s}^{-1}}\] \[v=2.18\times {{10}^{6}}\times \frac{1}{3}=726.67\times {{10}^{3}}m{{s}^{-1}}\] Number of revolutions per second\[=\frac{v}{2\pi r}\] \[=\frac{726.67\times {{10}^{3}}}{2\times 3.14\times \left( 0.0529\times {{10}^{-9}}\times \frac{32}{1} \right)}\] \[=2.43\times {{10}^{14}}\]revolution per second


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