CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to \[\frac{1}{4}\]th of the initial volume, the reaction rate relating to original rate will be

    A)  \[\frac{1}{10}\]                               

    B)  \[\frac{1}{8}\]

    C)  \[8\]                                    

    D)  \[16\]

    Correct Answer: D

    Solution :

                    Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate\[=k(4a)\,(4b)=16\,kab=16\]times


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