CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    At a particular locus the frequency of A allele is 0.6 and that of a is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

    A)  0.36                                      

    B)  0.16

    C)  0.24                                      

    D)  0.48

    Correct Answer: D

    Solution :

                    Hardy-Weinberg equilibrium states that these is a balance in the relative number of alleles. That is maintained within a large population over a period of time \[{{p}^{2}}+2pq+{{q}^{2}}=1\] \[p=0.6\] and \[q=0.4\] (given) \[\therefore \] 2\[pq\](frequency of heterozygote) \[=2\times 0.6\times 0.4=0.48\]


You need to login to perform this action.
You will be redirected in 3 sec spinner