A) 4.0 V
B) 3.0 V
C) 2.5 V
D) 2.0 V
Correct Answer: C
Solution :
\[I=\frac{6-2}{20+5+R}\] \[I=\frac{4}{25+R}\] \[0.1=\frac{4}{25+R}\] \[40=25+R\] \[R=15\,\Omega \] The current of 0.1 A must flow from x to y through R \[{{V}_{x}}+6-(0.1)\,(15)-2-{{V}_{y}}=0\] \[{{V}_{x}}+6-1.5-2-{{V}_{y}}=0\] \[{{V}_{x}}-{{V}_{y}}=2.5\,V\]You need to login to perform this action.
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