A) 400 N-m
B) 60 N-m
C) 40 N-m
D) 80 N-m
Correct Answer: D
Solution :
Power delivered by engine \[p=\tau \omega \] \[20\times 746=\tau \left( 1800\times \frac{2\pi }{60} \right)\] \[\tau =\frac{20\times 746\times 60}{1800\times 2\pi }\] \[\tau =80\,N\text{-}m\]
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