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CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    A body of mass 10 kg falls from a height of 5m (g = 10\[m\text{/}{{s}^{2}}\]) and is stopped with in one-tenth of a second on the ground. The force of interaction is

    A)  100 N                                   

    B)  Zero

    C)  1000 N                

    D)  1100 N

    Correct Answer: D

    Solution :

                    From the condition \[(F-mg)\,t=mv\] \[(F-100)\frac{1}{10}=10\times \sqrt{2\times 10\times 5}\]    \[(\because v=\sqrt{2gh})\] \[F-100=10\times 10\times 10\] \[F-100=1000\] \[F=1000+100=1100N\]


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