A) inner orbits of atom
B) free electron existing in nuclei
C) decay of neutron in the nucleus
D) photon escaping from the nucleus
Correct Answer: C
Solution :
In beta decay, a beta minus particle \[({{\beta }^{-}})\]is an electron emission of \[\beta \] involves, transfor-mation of a neutron into a proton an electron and a third particle called an anti-neutrin\[(\bar{v}).\] \[_{0}{{n}^{1}}={{\,}_{1}}{{p}^{1}}+{{\,}_{-1}}\,{{\beta }^{0}}+\bar{v}\]
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