A) \[Xe{{F}_{6}}>Xe{{F}_{4}}>Xe{{F}_{2}}\]
B) \[Xe{{F}_{2}}>Xe{{F}_{4}}>Xe{{F}_{6}}\]
C) \[Xe{{F}_{2}}>Xe{{F}_{4}}<Xe{{F}_{6}}\]
D) \[Xe{{F}_{2}}=Xe{{F}_{4}}<Xe{{F}_{6}}\]
E) \[Xe{{F}_{2}}>Xe{{F}_{4}}=Xe{{F}_{6}}\]
Correct Answer: C
Solution :
Due to the availability of electron on \[Xe\,(c)\]\[Xe{{F}_{2}}>Xe{{F}_{4}}>Xe{{F}_{6}}\]is the correct order of basicity. \[Xe{{F}_{6}}\to \] one lone pair \[Xe{{F}_{4}}\to \] two lone pairs \[Xe{{F}_{2}}\to \] three lone pairs
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