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CMC Medical CMC-Medical VELLORE Solved Paper-2015

  • question_answer
    Consider the fission process of decay\[\overset{236}{\mathop{A}}\,\xrightarrow{{}}\overset{144}{\mathop{B}}\,+\,\,\overset{89}{\mathop{C}}\,\,+3n\] If the approximate binding energy per nucleon is             7 MeV for A, 8MeV for B, and 8MeV for C, then the energy referred in decay of one nucleus of A will be

    A)  208 MeV            

    B)  205 MeV

    C)  203 MeV            

    D)  212 MeV

    E)  223 MeV

    Correct Answer: D

    Solution :

                    Energy released = 144\[\times \]BE per nucleon tor B + 89\[\times \]BE per  nucleon for C \[-\]236\[\times \]BE per nucleon for A \[=144\times 8+89\times 8-236\times 7\] \[=(144\times 89)\times 8-236\times 7\] \[=1864-1652=212\text{ }MeV\]


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