An ideal spring with spring constant k = 200 N/m is fixed on one end of a wall. If the spring is pulled with a force 10 N at the other end along its length, how much it will be extended?
A) 5 cm
B) 2m
C) 2 cm
D) 5 m
Correct Answer:
A
Solution :
From Hookes law, \[F=-kx\] So,\[10=200\times x\Rightarrow x=\frac{10}{200}=0.05m=5cm\]