A) Zero
B) 5 N
C) 4 N
D) 25 N
Correct Answer: D
Solution :
Applied force \[=m\times a=5\times 5\] = 25 Limiting friction \[=\mu \,mg=0.8\times 5\times 10\] = 40 For the given condition applied force is very smaller than limiting friction \[\therefore \] Static friction on a body = applied force \[=ma\] \[=5\times 5\] \[=25\,N\]You need to login to perform this action.
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