A) 506 Hz
B) 516 Hz
C) 508 Hz
D) 518 Hz
Correct Answer: D
Solution :
Number of beats per second \[{{n}_{1}}-{{n}_{2}}=6\] Given: frequency of tuning fork A = 512 Hz Hence, frequency of B is \[512\text{ }\pm \text{ }6\] Hence, frequency of B is either \[=506Hz\]or \[518\,Hz\] After loading the fork 5, the frequency decreases Hence, frequency of fork B become \[512\pm B=4\] \[B=516\]or 508 Therefore, the frequency of fork before loading must be 518 Hz.You need to login to perform this action.
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