A) 75%
B) 87.5%
C) 93.75%
D) 92.5%
Correct Answer: C
Solution :
The amount of substance left after 4 half-lifes is N. \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}=100{{\left( \frac{1}{2} \right)}^{4}}=6.25%\] \[\therefore \] The fraction of element disintegrated \[={{N}_{0}}-N\] \[=100-6.25=93.75%\]You need to login to perform this action.
You will be redirected in
3 sec