A) 10
B) 15
C) 20
D) 60
Correct Answer: C
Solution :
As, 8 enzyme molecules catalysed = 1000 substrate molecule \[\therefore \] 1 enzyme molecule will catalyse = 125 substrate molecules. Since in 5 minutes,80% of substrate converted into product ie, \[\frac{125\times 80}{100}\]part of substrate is converted into product. \[\therefore \] In 1 minute, the number of molecules catalyses by 1 enzyme molecule \[=\frac{125\times 80}{100\times 5}=20\] Hence, die turnover of enzyme is 20.You need to login to perform this action.
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