A) 3.2 A- m2
B) 1.6 A- m2
C) 6.4 A- m2
D) 0.8 A- m2
Correct Answer: A
Solution :
\[{{B}_{H}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{{{r}^{3}}}\] \[4\times {{10}^{-5}}={{10}^{-7}}\times \frac{M}{{{(20)}^{3}}{{10}^{-6}}}\] \[\frac{{{(20)}^{3}}\times 4\times {{10}^{-5}}\times {{10}^{-6}}}{{{10}^{-7}}}=M\] \[M=3.2\,A{{m}^{2}}\]You need to login to perform this action.
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