A) ethylene chlorohydric is distilled with concentrated potassium hydroxide solution
B) ethylene bromide is boiled with sulphuric acid
C) ethene is treated with an alkaline potassium permanganate solution
D) propene is treated with water in the presence of sulphuric acid
Correct Answer: C
Solution :
\[\underset{Ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}O+[O]\xrightarrow[KOH]{cold\,KMn{{O}_{4}}\,(1%)}\] \[\underset{Ethylene\,glycol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,\]
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