A) \[7\]
B) \[6\]
C) \[9\]
D) \[8\]
Correct Answer: C
Solution :
Since, \[_{7}{{N}^{14}}\] is obtained from the parent element after two successive \[\beta \]-emission hence, the atomic number of parent element should be two units less than \[_{7}{{N}^{14}}\]i.e., the atomic number of parent element is 5, mass number of parent element is 14. Since, there is no change in mass number in \[\beta \]-emission. So, the number of neutrons in the parent nucleus = mass number - atomic number. \[=14-5=9\]
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