A) \[0.4\]
B) \[1.5\]
C) \[4.0\]
D) \[15.3\]
Correct Answer: D
Solution :
Normality of \[N{{H}_{3}}\] solution \[=\frac{26\times 1000}{17\times 100}=\frac{260}{17}\] \[=15.3\]
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