A) \[19.3\times {{10}^{4}}\]
B) \[17.8\times {{10}^{4}}\]
C) \[24.93\times {{10}^{9}}\]
D) \[17.8\times {{10}^{8}}\]
Correct Answer: B
Solution :
Most probable velocity (MPV) \[\sqrt{\frac{8RT}{\pi M}}\] Given, \[T={{27}^{o}}C=(27+273)=300\text{ }K\] Molecular mass of \[{{H}_{2}}=2g\,mo{{l}^{-1}}\] \[R=8.314\times {{10}^{7}}\,erg\,{{K}^{-1}}\,mol{{e}^{-1}}\] \[MP{{V}_{{{H}_{2}}}}=\sqrt{\frac{8\times 8.314\times {{10}^{7}}\times 300}{3.14\times 2}}\] \[=17.8\times {{10}^{4}}cm/sec\]
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