Haryana PMT Haryana PMT Solved Paper-1999

  • question_answer
    The freezing point of a \[0.05\]molal solution of a non-electrolyte in water is:

    A)  \[-{{0.093}^{o}}C\]        

    B)  \[{{1.86}^{o}}C\]

    C)  \[{{0.93}^{o}}C\]            

    D)  \[{{0.093}^{o}}C\]

    Correct Answer: A

    Solution :

                    \[\Delta {{T}_{f}}={{K}_{f}}\times m\] \[=1.86\times 0.05\] \[={{0.093}^{o}}\] Freezing point of the solution. = freezing point of solvent \[-\Delta {{T}_{f}}\]                 \[={{0}^{o}}C-{{0.093}^{o}}C\]                 \[=-{{0.093}^{o}}C\]


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