Haryana PMT Haryana PMT Solved Paper-1999

  • question_answer
    By the action of cone. \[HCl\] on potassium chlorate we get:

    A)  \[{{O}_{2}}+C{{l}_{2}}+Cl{{O}_{2}}\]

    B)  \[C{{l}_{2}}+Cl{{O}_{2}}\]

    C)  \[{{O}_{2}}+Cl{{O}_{2}}\]      

    D)  \[C{{O}_{2}}+C{{l}_{2}}\]

    Correct Answer: B

    Solution :

                    \[2KCl{{O}_{3}}+4HCl\xrightarrow{{}}2KCl+C{{l}_{2}}+2Cl{{O}_{2}}+2{{H}_{2}}O\]


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