A) \[12\times \frac{3}{\sqrt{7}}cm\]
B) \[12\times 3\times \sqrt{7}cm\]
C) \[12\times \sqrt{5/3}\]
D) \[12\times 3\times \sqrt{5}\]
Correct Answer: A
Solution :
Using the relation for radius of circle \[r=\frac{h}{{{\mu }^{2}}-1}\] Here, \[h=12cm,\,\mu =\frac{4}{3}\] or \[r=\frac{12}{\sqrt{{{(4/3)}^{2}}-1}}=\frac{12\times 3}{\sqrt{7}}\]
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