A) \[\frac{\omega (M+2m)}{M}\]
B) \[\frac{\omega M}{(M-2m)}\]
C) \[\frac{\omega (M-2m)}{(M+2m)}\]
D) \[\frac{\omega M}{(M+2m)}\]
Correct Answer: D
Solution :
Since, external torque is zero So, angular momentum of system is constant \[{{j}_{1}}={{j}_{2}}\] or \[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] \[M{{R}^{2}}\omega =(M{{R}^{2}}+m{{R}^{2}}+m{{R}^{2}})\omega \] So, \[\omega =\left( \frac{M}{M+2m} \right)\omega =\frac{M\omega }{(M+2m)}\]
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