Haryana PMT Haryana PMT Solved Paper-2000

  • question_answer
    In a transverse progressive wave of amplitude A the maximum particle velocity is four times of its wave velocity. The wavelength of the wave is:

    A) \[\frac{\pi A}{4}\]                                           

    B) \[\frac{\pi A}{2}\]

    C) \[2\pi A\]                                            

    D) \[4\pi A\]

    Correct Answer: B

    Solution :

                     Not Available


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