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Haryana PMT Haryana PMT Solved Paper-2001

  • question_answer
    The energy of an electron in the first Bohr orbit of H-atom is\[-13.6eV\]. The possible energy value(s) of the excited state(s) for electron in Bohr orbits of hydrogen is(are):

    A)  \[-6.8eV\]                         

    B)  \[-4.2eV\]

    C)  \[-3.4eV\]         

    D)  \[+6.8eV\]

    Correct Answer: C

    Solution :

                    \[{{E}_{1}}\] for \[H=-13.6eV.\] \[{{E}_{n}}\] for \[H=\frac{{{E}_{1}}}{{{n}^{2}}e}\] Thus,     \[{{E}_{2}}=\frac{-13.6}{4}=-3.4eV\]                 \[{{E}_{3}}=\frac{-13.6}{9}=-1.51eV\]                 \[{{E}_{4}}=\frac{-13.6}{16}=-0.85\] and so on


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