A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: D
Solution :
Both \[{{C}_{2}}{{H}_{2}}\]and \[{{C}_{2}}{{H}_{4}}\] are unsaturated hydrocarbons and both decolourise bromine in \[CC{{l}_{4}}\], but only \[{{C}_{2}}{{H}_{2}}\] gives precipitate with ammonical \[AgN{{O}_{3}}\].
You need to login to perform this action.
You will be redirected in
3 sec
