A) \[90{}^\circ \]
B) \[0{}^\circ \]
C) \[180{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: B
Solution :
\[\cos \theta =\frac{\overrightarrow{A}\overrightarrow{B}}{|\overrightarrow{A}||\overrightarrow{B}|}\] \[=\frac{(3\times 3)+(4\times 4)+(5\times 5)}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}}\] \[=\frac{9+16+25}{\sqrt{50}\sqrt{50}}=\frac{50}{50}\] \[=1=\cos 0\] \[\theta ={{0}^{o}}\]
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