A) \[C{{u}^{2+}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[Ne\]
D) \[M{{g}^{2+}}\]
Correct Answer: B
Solution :
\[Ca(20)=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\,4{{s}^{2}}\] \[C{{u}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\] Number of electrons in \[C{{a}^{2+}}=18\] Same number of electrons i.e. 18 are present in \[{{C}_{2}}{{H}_{6}}\].
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