A) \[s{{p}^{3}}>s{{p}^{2}}>sp\]
B) \[sp>s{{p}^{2}}>s{{p}^{3}}\]
C) \[s{{p}^{3}}>sp>s{{p}^{2}}\]
D) \[s{{p}^{2}}>sp>s{{p}^{3}}\]
Correct Answer: B
Solution :
s-character in sp-hybrid orbital = 50% s-character in \[s{{p}^{2}}\]hybrid orbital =33% s-character in \[s{{p}^{3}}\]hybrid orbital =25% Decreasing order \[sp>s{{p}^{2}}>s{{p}^{3}}\]
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