A) has two hydroxyl groups in its structure
B) is a derivative of sulphur dioxide
C) is a dibasic acid
D) has greater affinity for water
Correct Answer: A
Solution :
\[PC{{l}_{5}}+HO-\underset{O}{\mathop{\underset{||}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,}}\,}}\,-OH\xrightarrow{{}}\]\[Cl-\underset{O}{\mathop{\underset{||}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,}}\,}}\,-Cl+POC{{l}_{3}}+{{H}_{2}}O\]\[PC{{l}_{5}}\] attacks \[-OH\] group and replace it by \[-Cl\] group. Hence, reaction of \[PC{{l}_{5}}\] with \[{{H}_{2}}S{{O}_{4}}\] shows the presence of \[2-OH\] groups in \[{{H}_{2}}S{{O}_{4}}\].
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