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Haryana PMT Haryana PMT Solved Paper-2005

  • question_answer
    A resistor R has power dissipation P with cell voltage E. The resistor is cut in n equal parts and all parts are connected in parallel with same cell. The new power dissipation is :

    A)  \[np\]                                 

    B)  \[n{{p}^{2}}\]

    C)  \[{{n}^{2}}p\]                                  

    D)  \[n/p\]

    Correct Answer: D

    Solution :

                    The resistance of each part = R/n The effective resistance becomes \[R/{{n}^{2}}\] Since, the battery voltage is constant so,          \[P\propto \frac{1}{R}\]  \[\Rightarrow \]  \[\frac{p}{P}=\frac{R}{R/{{n}^{2}}}\]\[\Rightarrow \]\[P={{n}^{2}}P\]


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