A) \[27,192\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[98.304\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[38.72\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) Data are insufficient to calculate it
Correct Answer: B
Solution :
According to Troutons law, \[\frac{\Delta {{H}_{p}}}{{{T}_{b}}}=88\,J{{K}^{-1}}\,mo{{l}^{-1}}\] \[\therefore \] \[\Delta {{H}_{\upsilon }}=88\times 309\] \[=27192\,J\,mo{{l}^{-1}}\] \[=27.912kJ\,mo{{l}^{-1}}\]
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