A) base
B) acid
C) reducing agent
D) catalyst
Correct Answer: D
Solution :
In nitrating mixture \[(conc.\,HN{{O}_{3}}+conc.\,{{H}_{2}}S{{O}_{4}})\]. ) cone. \[HN{{O}_{3}}\] acts as base i.e., it accepts proton and give nitronium ion (the electrophile). \[HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{nitronium\,ion}{\mathop{\underset{NO_{2}^{+}}{\mathop{\underset{\downarrow {{H}_{2}}O}{\mathop{{{H}_{2}}NO_{3}^{+}}}\,}}\,}}\,+HSO_{4}^{-}\]
You need to login to perform this action.
You will be redirected in
3 sec
