A) \[A{{g}_{2}}S{{O}_{4}}\]
B) \[Cu{{F}_{2}}\]
C) \[Mg{{F}_{2}}\]
D) \[CuCl\]
Correct Answer: B
Solution :
\[C{{u}^{2+}}\] ion is coloured (blue) as it has unpaired electrons. \[C{{u}^{2+}}=[Ar]3{{d}^{9}}\]
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