A) \[0\]
B) \[1/2\]
C) \[3/2\]
D) \[2\]
Correct Answer: A
Solution :
We know that, \[{{t}_{1/2}}\propto {{C}^{1-n}}\](where k is the order of reaction) \[\therefore \] \[\frac{{{({{t}_{1/2}})}_{1}}}{{{({{t}_{1/2}})}_{2}}}={{\left( \frac{{{C}_{1}}}{{{C}_{2}}} \right)}^{1-n}}\] or \[\frac{50}{25}={{\left( \frac{C}{4C} \right)}^{1-n}}\] or \[2={{\left( \frac{1}{4} \right)}^{1-n}}\] or \[2={{(2)}^{2n-2}}\] or \[2n-2=1\] \[n=\frac{3}{2}\] Hence, the order of reaction = 3/2
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